When
cutting an internal thread the linear feedrate has to be reduced to
compensate for the ratio of the tool's cutting diameter to the major
diameter being cut. If you do not compensate, the feedrate that the
cutting edge sees will be much greater and tool failure will occur. The threadmilling feedrate is equal to:
((major diameter - cutter diameter)/major diameter) x linear feedrate
Example #1
Thread Diameter to be cut (D2): 3/8
Threadmill Diameter (D1): .285
If the linear
feedrate calculated from the feeds and speeds above came out to be 10 IPM
the programmed feedrate for the internal threadmilling cut would be: ((D2-D1)/D2)
* linear feedrate or ((.375-.285)/.375)*10 or 2.4 inches per minute
Example #2
If you were going to cut a 1/2-13 thread in a low alloy steel that was
less than 25 Rc hardness:
Question:
Which tool would you use?
Answer: #TM50013 which has a .350 cutter diameter and
4 flutes
Question:
What surface speed should you run?
Answer:
350 - 500 (We will use 400 SFM)
Question:
What is the chipload per tooth?
Answer:
.0025-.0035 per tooth (We will use .003"/tooth)
How do you
calculate RPM's?
Take 3.8 divided by the threadmill dia and multiply by the SFM
Example: ((3.8/.350) * 400 SFM = 4343 rpm
How do you
calculate linear inches per minute?
Take the ("/tooth) * (# of flutes) * RPM's
Example: ((.003" * 4 flutes) * 4343 RPM's = 52 linear "/min
What will be the
programmed feedrate when cutting a 1/2-13 internal thread?
Answer:((D2-D1)/D2) * linear feedrate or ((.500 -
.350)/ .500) * 52 ipm = 15.6 IPM |